一种最坏情况线性运行时间的选择算法 - The missing worst-case linear-time Select algorithm in CLRS.

2022-11-25,,,,

一种最坏情况线性运行时间的选择算法 - The missing worst-case linear-time Select algorithm in CLRS.

选择算法也就是求一个无序数组中第K大(小)的元素的值的算法,同通常的Top K等算法密切相关。

在CLRS中提到了一种最坏情况线性运行时间的选择算法,在书中给出了如下的文字描述(没有直接给出伪代码)。

1.Divide n elements into groups of 5
2.Find median of each group (How? How long?)
3.Use Select() recursively to find median x of the n/5 medians
4.Partition the n elements around x. Let k = rank(x)
5.if (i == k) then return x
if (i < k) then use Select() recursively to find ith smallest element in first partition
else (i > k) use Select() recursively to find (i-k)th smallest element in last partition

后来在MIT公开课网站上找到了这个课件。给出了几段伪代码,但是比上面的文字描述强不了多少;

得了还是自己动手丰衣足食吧;

代码中给出了同STL标准Select算法、一般SELECT和随机化的SELECT算法的运行效率比较分析;

现以C++实现了该选择算法,以供参考。

//determines the ith smallest element of an input array.
#include <iostream>
#include <algorithm>
#include <ctime>
#include <cassert> using namespace std; #include "randomized_select.cpp" size_t my_ceil(size_t m, size_t n)
{
size_t mul, rem;
mul = m / n;
rem = m % n;
if (rem > 0)
mul++;
return mul;
} size_t my_floor(size_t m, size_t n)
{
return m / n;
} template <class T>
void exchange(T& x, T& y)
{
T t = x; x = y; y = t;
} template <class T>
void insertion_sort(T *a, size_t n)
{
int i, j;
for (j = 1; j < (int) n; ++j) {
T key = a[j];
// insert a[j] into the sorted sequence a[0..j-1].
i = j - 1;
while (i >= 0 && a[i] > key) { //>= or >
a[i + 1] = a[i];
i--;
}
a[i + 1] = key;
}
} template <class T>
size_t partition(T *a, size_t p, size_t r)
{
T x = a[r];
int i = p - 1, j; //XXX in case of negative.
for (j = p; j < (int) r; ++j)
if (a[j] <= x) //XXX <= or <
exchange(a[++i], a[j]);
exchange(a[i + 1], a[r]);
return i + 1;
} // find index of element x in array a of size n.
template <class T>
size_t index_of(T *a, size_t n, T x)
{
size_t i;
for (i = 0; i < n; ++i)
if (a[i] == x)
return i;
return i;
} // partition around pivot on index i
template <class T>
size_t partition_x(T *a, size_t n, T x)
{
if (n == 1) //XXX zero based index.
return 0;
size_t p, r, i; // [p, r]
p = 0;
r = n - 1;
i = index_of(a, n, x);
if (i >= n)
cout << "i=" << i << "; n=" << n << endl;
assert(i < n); //XXX not found!
exchange(a[i], a[r]);
return partition(a, p, r);
} #ifndef NDEBUG
#define NDEBUG
#endif // select from [p,r]
template <class T>
T select(T *a, size_t n, size_t i)
{
if (n < 2) // 0,1
return a[0]; //XXX // 1: divide n elements into groups of 5.
size_t ng = my_floor(n, 5); // ng group with 5 elements.
size_t ng1 = my_ceil(n, 5); // ng1 >= ng.
size_t rem = n - ng * 5; // elements in last group. #ifndef NDEBUG
cout << "i=" << i << "; n=" << n << "; ng=" << ng << "; ng1=" << ng1 << endl;
#endif // 2: find median of each group.
// sort each group.
for (size_t j = 0; j < ng; ++j)
insertion_sort(&a[5 * j], 5);
// sort last group(or only group).
if (rem > 0)
insertion_sort(&a[5 * ng], rem); // picking medians
T *medians = new T[ng1];
for (size_t j = 0; j < ng; ++j)
medians[j] = a[5 * j + 2];
// picking the last median.
if (rem > 0) {
size_t last_mi = ng * 5 - 1 + my_ceil(rem, 2); // (start+end)/2 floor.
medians[ng] = a[last_mi];
} // 3: use select recursively to find median x of the medians.
// partition on median-of-medians.
size_t mmi = my_ceil(n, 10) - 1;
T x = select(medians, ng1, mmi);
delete [] medians; //XXX break; #ifndef NDEBUG
cout << "(before partition); x=" << x.value << ";" << endl;
for (size_t y = 0; y < 5; y++) {
for (size_t x = 0; x < ng; x++)
if (gp[x].e[y].is_infinite)
cout << "*" << "\t";
else
cout << gp[x].e[y].value << "\t";
cout << endl;
}
#endif // 4: partition input array around pivot x.
size_t k = partition_x(a, n, x); #ifndef NDEBUG
cout << "(after partition); k=" << k << endl;
for (size_t y = 0; y < 5; y++) {
for (size_t x = 0; x < ng; x++)
if (gp[x].e[y].is_infinite)
cout << "*" << "\t";
else
cout << gp[x].e[y].value << "\t";
cout << endl;
}
cout << endl;
#endif if (i == k) // DONE!
return a[k]; // value of pivot.
else if (i < k) // L array.
return select(a, k, i);
else // if (i > k) // G array,
return select(a + k + 1, n - k - 1, i - k - 1);
} // ith from 0.
template <class T>
T try_select(T *a, size_t n, size_t ith)
{
clock_t beg = clock(); T x = select(a, n, ith); // [0,n-1] clock_t end = clock();
cout << "Select take " << (double) (end - beg) / CLOCKS_PER_SEC << " sec." << endl; return x;
} // ith start from 0.
int try_std_select(int *a, size_t n, size_t ith)
{
clock_t beg = clock();
nth_element(a, a + ith + 1, a + n);
clock_t end = clock();
cout << "STD take " << (double) (end - beg) / CLOCKS_PER_SEC << " sec." << endl;
return a[ith];
} // ith start from 1.
int try_rand_select(int *a, size_t n, size_t ith)
{
clock_t beg = clock();
int ie = randsel::randomized_select(a, 0, n - 1, ith + 1);
clock_t end = clock();
cout << "random select take " << (double) (end - beg) / CLOCKS_PER_SEC << " sec." << endl;
return ie;
} void select_test()
{
cout << "please choose the select algorithm: " << endl
<< "1: my select(default); 2: std nth_element; 3: random select;" << endl;
int choice;
cin >> choice; #define _1K (1024)
#define _1M (_1K*_1K)
#define _1G (_1K*_1M)
#define _256M (256*_1M) //2^26 // 1k, 1m, 256m
for (size_t n = _1K; n <= _256M; ) { int *a = new int[n]; for (size_t j = 0; j < n; ++j)
a[j] = j * 10;
random_shuffle(a, a + n);
int ith = n / 2; cout << endl << "=============== n=" << n << ", i=" << ith << " ==============" << endl;
int ie; switch (choice)
{
case 1:
ie = try_select(a, n, ith); // zero based index.
break;
case 2:
ie = try_std_select(a, n, ith);
break;
case 3:
ie = try_rand_select(a, n, ith);
break;
default:
ie = try_select(a, n, ith); // zero based index.
break;
} cout << ith << "-th:" << ie << endl;
assert(ie == ith * 10); delete [] a; // level.
if (n == _1K)
n = _1M;
else if (n == _1M)
n = _256M;
else if (n == _256M)
n = _1G;
else
n = _1G;
}
}

 
 

 
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