N个整数(数的大小为0-255)的序列,把它们加密为K个整数(数的大小为0-255).再将K个整数顺序随机打乱,使得可以从这乱序的K个整数中解码出原序列。设计加密解密算法,且要求K<=15*N.

2023-06-25,,

N个整数(数的大小为0-255)的序列,把它们加密为K个整数(数的大小为0-255).再将K个整数顺序随机打乱,使得可以从这乱序的K个整数中解码出原序列。设计加密解密算法,且要求K<=15*N.

如果是:

N<=16,要求K<=16*N.
N<=16,要求K<=10*N.
N<=64,要求K<=15*N.

#include <iostream>
using namespace std;

void printArray(int* arr, int len) {
	if (!arr) {
		return;
	}
	for (int i = 0; i < len; ++i) {
		cout << arr[i] << " ";
	}
	cout << endl;
}

int cmp(const void *a, const void *b) {
	int aa = (*(const int*) a) >> 4;
	int bb = (*(const int*) b) >> 4;
	return aa - bb;
}

int cmp1(const void *a, const void *b) {
	int aa = (*(const int*) a) >> 2;
	int bb = (*(const int*) b) >> 2;
	return aa - bb;
}

void disorder(int* arr, int len) {
	srand((int) time(NULL));
	for (int i = 0; i < len; i++) {
		int tmp = rand() % len;
		swap(arr[i], arr[tmp]);
	}
}

int* encrypt1(int* arr, int len, int k) {
	int id = 0;

	int* encryptArr = new int[k * len];
	memset(encryptArr, 0, sizeof(int) * k * len);
	for (int i = 0; i < len; ++i) {
		int index = (i << 4);
		int prev = arr[i] >> 4;
		int last = arr[i] & 15;
		for (int j = 0; j < k - 8; ++j, id++) {
			encryptArr[id] = index | prev;
		}
		for (int j = 0; j < 8; ++j, id++) {
			encryptArr[id] = index | last;
		}
	}

//	printArray(encryptArr, k * len);
	disorder(encryptArr, k * len);

	return encryptArr;
}

int* encrypt2(int* arr, int len, int k) {
	int id = 0;

	int* encryptArr = new int[k * len];
	memset(encryptArr, 0, sizeof(int) * k * len);
	for (int i = 0; i < len; ++i) {
		int index = (i << 2);
		int data1 = arr[i] >> 6;
		int data2 = (arr[i] >> 4) & 3;
		int data3 = (arr[i] >> 2) & 3;
		int data4 = arr[i] & 3;

		encryptArr[id++] = index | data1;

		for (int j = 0; j < 2; ++j, id++) {
			encryptArr[id] = index | data2;
		}

		for (int j = 0; j < 4; ++j, id++) {
			encryptArr[id] = index | data3;
		}

		for (int j = 0; j < 8; ++j, id++) {
			encryptArr[id] = index | data4;
		}
	}

//	printArray(encryptArr, k * len);
	disorder(encryptArr, k * len);

	return encryptArr;
}

int* decrypt1(int* encryptArr, int len, int k) {
	qsort(encryptArr, k * len, sizeof(int), cmp);
//	printArray(encryptArr, k * len);

	int* decryptArr = new int[len];
	memset(decryptArr, 0, sizeof(int) * len);
	int prev = 0;
	int last = 0;
	int count1 = 0;
	int count2 = 0;
	int index = 0;
	for (int i = 0; i < k * len; i += k) {
		prev = encryptArr[i];
		count1 = 1;
		count2 = 0;
		for (int j = i + 1; j < i + k; ++j) {
			if (prev == encryptArr[j]) {
				count1++;
			} else {
				last = encryptArr[j];
				count2++;
			}
		}
		if (count1 > k - 8) {
			if (count1 == k) {	//加密前prev,last相同
				last = prev;
			}
			swap(last, prev);
		} else if (count2 > k - 8) {
			if (count2 == k) {
				prev = last;
			}
		}
		prev &= 15;
		last &= 15;
		prev <<= 4;
		decryptArr[index++] = prev | last;
	}

	return decryptArr;
}

int* decrypt2(int* encryptArr, int len, int k) {
	qsort(encryptArr, k * len, sizeof(int), cmp1);
//	printArray(encryptArr, k * len);

	int* decryptArr = new int[len];
	memset(decryptArr, 0, sizeof(int) * len);
	int* data = new int[4];
	int* count = new int[4];
	int index = 0;
	int id = 1;
	for (int i = 0; i < k * len; i += k) {
		memset(data, -1, 4 * sizeof(int));
		memset(count, 0, 4 * sizeof(int));
		data[0] = encryptArr[i];
		count[0] = 1;
		id = 1;
		for (int j = i + 1; j < i + k; ++j) {
			if (encryptArr[j] == data[0]) {
				count[0]++;
			} else if (encryptArr[j] == data[1]) {
				count[1]++;
			} else if (encryptArr[j] == data[2]) {
				count[2]++;
			} else if (encryptArr[j] == data[3]) {
				count[3]++;
			} else if (id < 4) {
				data[id] = encryptArr[j];
				count[id]++;
				id++;
			}
		}
		int data1 = -1;
		int data2 = -1;
		int data3 = -1;
		int data4 = -1;
		for (int i = 0; i < 4; ++i) {
			if (!count[i]) {
				break;
			}
			switch (count[i]) {
			case 1:
				data1 = data[i] & 3;
				break;
			case 2:
				data2 = data[i] & 3;
				break;
			case 4:
				data3 = data[i] & 3;
				break;
			case 8:
				data4 = data[i] & 3;
				break;
			case 3:
				data1 = data2 = data[i] & 3;
				break;
			case 5:
				data1 = data3 = data[i] & 3;
				break;
			case 9:
				data1 = data4 = data[i] & 3;
				break;
			case 6:
				data2 = data3 = data[i] & 3;
				break;
			case 10:
				data2 = data4 = data[i] & 3;
				break;
			case 12:
				data3 = data4 = data[i] & 3;
				break;
			case 7:
				data1 = data2 = data3 = data[i] & 3;
				break;
			case 11:
				data1 = data2 = data4 = data[i] & 3;
				break;
			case 13:
				data1 = data3 = data4 = data[i] & 3;
				break;
			case 14:
				data2 = data3 = data4 = data[i] & 3;
				break;
			}

		}
		decryptArr[index] |= data1 << 6;
		decryptArr[index] |= data2 << 4;
		decryptArr[index] |= data3 << 2;
		decryptArr[index] |= data4;

		index++;

	}
	return decryptArr;
}

int* encryptChoice(int* arr, int len, int n, int k) {
	int* encryptArr = NULL;
	if (n == 16) {
		if (len > n) {
			return NULL;
		}
		if (k == 16) {
			k = 12;
			encryptArr = encrypt1(arr, len, k);
		} else if (k == 10) {
			encryptArr = encrypt1(arr, len, k);
		}
	} else if (n == 64 && k == 15) {
		encryptArr = encrypt2(arr, len, k);
	}

	if (encryptArr) {
		cout << "n,k: " << n << "," << k << endl;
		cout << "加密数组:" << endl;
		printArray(encryptArr, k * len);
	}

	return encryptArr;
}

void decryptChoice(int* encryptArr, int len, int n, int k) {
	int* decryptArr = NULL;
	if (n == 16) {
		//int 是32bit
		if (len > n) {
			return;
		}
		if (k == 16) {
			k = 12;
			decryptArr = decrypt1(encryptArr, len, k);
		} else if (k == 10) {
			decryptArr = decrypt1(encryptArr, len, k);
		}
	} else if (n == 64 && k == 15) {
		decryptArr = decrypt2(encryptArr, len, k);
	}

	if (decryptArr) {
		cout << "解密数组:" << endl;
		printArray(decryptArr, len);
	}
}
int main() {
	int arr1[] =
			{ 12, 20, 51, 4, 7, 48, 32, 13, 41, 35, 44, 67, 55, 34, 54, 63 };
	int len = sizeof(arr1) / sizeof(int);

	int k = 16;
	int n = 16;
	int* encryptArr = NULL;
	encryptArr = encryptChoice(arr1, len, n, k);
	decryptChoice(encryptArr, len, n, k);

	k = 10;
	encryptArr = encryptChoice(arr1, len, n, k);
	decryptChoice(encryptArr, len, n, k);

	k = 15;
	n = 64;
	encryptArr = encryptChoice(arr1, len, n, k);
	decryptChoice(encryptArr, len, n, k);
	return 0;
}

N个整数(数的大小为0-255)的序列,把它们加密为K个整数(数的大小为0-255).再将K个整数顺序随机打乱,使得可以从这乱序的K个整数中解码出原序列。设计加密解密算法,且要求K<=15*N.的相关教程结束。

《N个整数(数的大小为0-255)的序列,把它们加密为K个整数(数的大小为0-255).再将K个整数顺序随机打乱,使得可以从这乱序的K个整数中解码出原序列。设计加密解密算法,且要求K<=15*N..doc》

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