[Algorithm] Array production problem

Given an array of integers, return a new array such that each element at index i of the new array is the product of all the numbers in the original array except the one at i.

For example, if our input was [1, 2, 3, 4, 5], the expected output would be [120, 60, 40, 30, 24]. If our input was [3, 2, 1], the expected output would be [2, 3, 6].

For example [1,2,3,4,5]:

We can divide into Right and Left array two parts. For Left[0] and Right[n-1], we set to 1;

 

We can get the product results like the image above.

Now the only thing we need to do is Left * Right. 

 

The way Left calculated is:

Left[i] = Left{i-1] * arr[i-1], i start from 1, i++

 

The way Right calculated is:

Right[j] = Right[j+1] * arr[j+1], j start from n-2, j--

 

function productArr(arr) {

  let left = [];

  let right = [];

  let prod = [];

  left[0] = 1;

  right[arr.length - 1] = 1;

  for (let i = 1; i <= arr.length -1; i++) {

    left[i] = left[i-1] * arr[i-1];

  }

  for (let j = arr.length - 2; j >=0; j--) {

    right[j] = right[j+1] * arr[j+1];

  }

  prod = left.map((l, i) => l * right[i]);

  return prod

}

console.log(productArr([1, 2, 3, 4, 5])); // [120, 60, 40, 30, 24]

[Algorithm] Array production problem的相关教程结束。