python实现鼠标手动截图(类似于QQ截图)

由于在网上找了很久，只找到按像素位置截图和全屏截图的，所以决定自己写一个。

本程序实现原理是现用PIL里的ImageGrab进行全屏截图，然后通过模拟鼠标操作，进行截图，最后删除全屏截图，只留下鼠标截图

代码如下:

import cv2

import time,PIL,os

from PIL import ImageGrab

import numpy as np

#截图

def cut():

    global img

    scrren_cut()

    img = cv2.imread('screen.jpg')

    cv2.namedWindow('image')

    cv2.setMouseCallback('image', on_mouse)

    cv2.imshow('image', img)

    cv2.waitKey(0)

    os.remove('screen.jpg')

def scrren_cut():

    beg = time.time()

    debug = False

    # img = ImageGrab.grab(bbox=(250, 161, 1141, 610))

    image = ImageGrab.grab()

    image.save("screen.jpg")

    # PIL image to OpenCV image

def on_mouse(event, x, y, flags, param):

    global img, point1, point2

    img2 = img.copy()

    if event == cv2.EVENT_LBUTTONDOWN:         #左键点击

        point1 = (x,y)

        cv2.circle(img2, point1, 10, (0,255,0), 5)

        cv2.imshow('image', img2)

    elif event == cv2.EVENT_MOUSEMOVE and (flags & cv2.EVENT_FLAG_LBUTTON):               #按住左键拖曳

        cv2.rectangle(img2, point1, (x,y), (255,0,0), 5)

        cv2.imshow('image', img2)

    elif event == cv2.EVENT_LBUTTONUP:         #左键释放

        point2 = (x,y)

        cv2.rectangle(img2, point1, point2, (0,0,255), 5)

        cv2.imshow('image', img2)

        min_x = min(point1[0],point2[0])

        min_y = min(point1[1],point2[1])

        width = abs(point1[0] - point2[0])

        height = abs(point1[1] -point2[1])

        cut_img = img[min_y:min_y+height, min_x:min_x+width]

        cv2.imwrite('cut.jpg', cut_img)

python实现鼠标手动截图(类似于QQ截图)的相关教程结束。