CF580D Kefa and Dishes (状压DP)

2022-10-22,

枚举最后食物

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
#define R(a,b,c) for(register int a = (b); a <= (c); ++ a)
#define nR(a,b,c) for(register int a = (b); a >= (c); -- a)
#define Max(a,b) ((a) > (b) ? (a) : (b))
#define Min(a,b) ((a) < (b) ? (a) : (b))
#define Fill(a,b) memset(a, b, sizeof(a))
#define Abs(a) ((a) < 0 ? -(a) : (a))
#define Swap(a,b) a^=b^=a^=b
#define ll long long #define ON_DEBUG #ifdef ON_DEBUG #define D_e_Line printf("\n\n----------\n\n")
#define D_e(x) cout << #x << " = " << x << endl
#define Pause() system("pause")
#define FileOpen() freopen("in.txt","r",stdin); #else #define D_e_Line ;
#define D_e(x) ;
#define Pause() ;
#define FileOpen() ; #endif struct ios{
template<typename ATP>ios& operator >> (ATP &x){
x = 0; int f = 1; char c;
for(c = getchar(); c < '0' || c > '9'; c = getchar()) if(c == '-') f = -1;
while(c >= '0' && c <= '9') x = x * 10 + (c ^ '0'), c = getchar();
x*= f;
return *this;
}
}io;
using namespace std;
#define int long long
int a[19], val[19][19], f[(1 << 18) + 7][19];
#undef int
int main(){
#define int long long
int n, m, k;
io >> n >> m >> k;
R(i,1,n)
io >> a[i]; R(i,1,k){
int x, y;
io >> x >> y;
io >> val[x][y];
}
R(i,1,n)
f[1 << (i - 1)][i]=a[i]; int ans = 0;
R(s,0,(1 << n) - 1){
int tot=0;
R(i,1,n)
if(s & (1 << (i - 1))){
++tot;
R(j,1,n)
if(!(s & (1 << (j - 1)))){
f[s | (1 << (j - 1))][j] = Max(f[s | (1 << (j - 1))][j] , f[s][i] + a[j] + val[i][j]);
}
}
if(tot == m)
R(i,1,n)
if(s & (1 << (i - 1)))
ans = Max(ans , f[s][i]);
} printf("%lld", ans); return 0;
}

CF580D Kefa and Dishes (状压DP)的相关教程结束。

《CF580D Kefa and Dishes (状压DP).doc》

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